A Plea for Pure Mathematics
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byJosef Böhm |
| BHAK
St.Pölten, DERIVE User Group and T3 AUSTRIA |
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I
am a teacher at a business college (high school level, 14-19 years) and
I have been working with CAS in teaching mathematics for a long time.
For many reasons I prefer DERIVE and I have prepared a lot of papers for
various purposes. In one of them we repeated and extended our knowledge
about GCD and LCM.
Unfortunately
was not possible to have regular access to the computer lab, because many
other subjects are more bound to the PC than mathematics. I tried to overcome
that obstacle. In last fall we - two colleagues and I - convinced the
parents of more than 150 students to buy a TI-92 to have a more interesting
and state-of-the-art mathematics education. I was teaching two forms and
after a short introduction into the handling of the machine (numerical
calculations, factorizing and expanding) I tried to do some "mathematics"
with my students (aged 15/16, approximately 65% female).
I´ll
present the worksheet and add some comments (all in Italics). It was interesting
and fascinating to observe the students´ attitude towards that kind of
mathematics and I did not find any real differencies in attitudes comparing
more or less gifted students
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| TI
92 Worksheet 3 |
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| Greatest
Common Divisor and Least Common Multiple (GCD and LCM) |
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Using
the -Menu
you can factorize almost any arbitrary large number into its prime factors.
So let´s try the pretty large number 844074000! (Set your device in Exact
Mode!)
factor(844074000)
= ................................................

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| (1) |
Using
that tool you can easily find the GCD of 844074000, 4765246200 and
45585540000. (Repeat first how to find the GCD of two or more numbers). |
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844074000
= .......................................... |
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4765246200
= ........................................ |
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45585540000
= ............................., hence GCD = ........................
= ......................... |
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| At that moment
students should revise a wellknown algorithm with larger numbers and
expressions than usual. That is possible now using a CAS.
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| If the number
found should represent the GCD, then all the quotients of the given
numbers and the "maybe - GCD" should not have any prime
factors in common. Check that now: |
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(Store
the GCD as ): ..........................
gcd |
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Try once
more but use another name because gcd is obviously in use.
So take:
cd. |
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844074000
: cd = ....................................... = ....................
(factorize !) |
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4765246200
: cd = ....................................... = .................... |
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45585540000
: cd = ....................................... = .................... |
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true
? (yes / no) ..................... |
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If your answer is
no then check your result !
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| (2) Can
we prove the statement given in the box above?: |
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| This is a
chance for the teacher to present a very easy to follow indirect proof.
Some lessons earlier we showed in a short introduction into logic
that a ® b is equivalent to Ø
b ® Ø
a. |
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We want to show:
If gcd(a,b) = T then gcd(a/T, b/T) = 1
We show that gcd(a/T,
b/T) ¹ 1 implies T is not the gcd of a and
b
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a
: T = qa = p*a |
(1) |
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b
: T = qb = p*ß |
(2) |
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| So |
a
= T * p * a and b = T * p * ß which
implies that T * p must be a "greater" common divisor than
T. And that is obviously a contradiction to the fact that gcd(a,b)
= T. |
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Find and check in
a similar way the GCDs of:
| (3) |
=
........................... |
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| (4) |
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| (Comment:
it seems that it is not possible to factorize general expressions and the
coefficients in one operation. Try to find an alternative!) |
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| (5) |

GCD = ......................................................................................... |
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| These examples
will force the students to check their data. They have to edit the
bulky expressions very carefully. |
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The
TI-92 knows the function gcd(number1,number2) for calculating the
GCD of number1 and number2.
Check that using two
randomly chosen pairs of numbers:
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| (6) Calculate
GCD(844074000, 45585540000, 4765246200) and compare with (1)! |
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| It was interesting
to observe students trying to find a way out of that trap. At last
they discovered the concept of a nested function. They immediately
tried to extend for four or more numbers. |
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How
could you use gcd for three or more numbers? |
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=
.......................................... |
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| (7) |
What
is the meaning of the abbreviation gcd? |
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................................................................................................... |
Have you ever tried gcd for non-integer numbers? Do that now and
report your results:
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GCD(.....................................)
= ...................................... |
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GCD(......................................)
= ...................................... |
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GCD(......................................)
=...................................... |
| Here we encourage
the students to generalize a wellknown rule in an unusual way. They
are asked to interpret the outcomes. |
Can you explain the outcomes?
I assume that you
have tried only rational numbers, take now at least one irrational number:
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GCD(......................................)
=...................................... |
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(8) I also assume
that you have worked with decimal numbers. It is "more mathematical"
to work with fractions:
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Interpret the results: |
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Does
your assertion hold also for ? |
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Is a new interpretation necessary? |
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| Now we are
learning that our first idea might not hold. We have to refine the
interpretation. |
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| (9) |
The
next task is to find the least common multiple for the numbers from
(1): |
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LCM
(844074000, 4765246200, 45585540000) = .............................................. |
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Apply
once more the nested function concept.
The main task in the next paragraph is not only to find that
check but also to verbalize the process and to check the validity
of the assumptions. |
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| (10) |
Consider
a check similar to that for the GCD! |
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Describe
the process: |
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Confirm
your assumption using the numbers from (9) |
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Find the LCMs for
the expressions from (3), (4) and (5). Check the result for at least one
of them:
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| (11) LCM(problem
3) = ............................................... |
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| (12) LCM(problem
4) = ............................................... |
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| (13) LCM(problem
5) = ............................................... |
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| (14) is not
interesting for English speaking students. But in Austria we call
the lcm "kleinstes gemeinsames Vielfaches" with the abbreviation
kgV. So this point forces them to use the manual and look carefully
for the function wanted. |
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| (14) |
Which function
of the TI-92 returns the LCM of two numbers: |
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................................... |
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(Use the manual!) |
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| (15) |
What is the meaning
of LCM for rational numbers? |
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| (16) |
I assure: |
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expressions a,b can easily be derived from the GCD(a,b) and the two
expressions. Find the relation! |
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Work systematically!
Start your investigation using smaller numbers and try to find a rule.
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a
= ....................; b = ....................., GCD(a,b) = ...................,
LCM(a,b) = .............. |
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a
= ....................; b = ....................., GCD(a,b) = ...................,
LCM(a,b) = .............. |
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a
= ....................; b = ....................., GCD(a,b) = ...................,
LCM(a,b) = .............. |
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a
= ....................; b = ....................., GCD(a,b) = ...................,
LCM(a,b) = .............. |
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There are
so many patterns in mathematics and from my point of view recognizing
patterns can very often help students solve their maths problems.
So give them many chances to train that ability.
The
next step is to express the pattern in a form - as one or more sentences,
as a rule, as a formula.
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| When you
are sure you know the relation then you should check your conjecture using
two "larger" numbers or expressions from the 1st sheet: |
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| You should
be able to express the relation as a formula: |
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GCD(a,b) = |
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Express this formula
in words:
Until now that conjecture
has only been an unproved conjecture and not a theorem. The proof is still
lacking. Try to follow carefully the exact proof:
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a = 8400, b = 1440
a = 24*3*52*7
and b = 25*32*5 (*70)
gcd(8400, 1440) =
24*31*51*70 and lcm(8400,
1440) = 25*32*52*71
gcd * lcm = 24+5
* 31+2 * 51+2 * 70+1 = a*b
Let us generalize:
a = p1x1
* p2x2 *............* pnxn
and b = p1y1 * p2y2 *............*
pnyn
(with n = greatest
prime factor occuring and if pk does not occur in one factorization
then xk or yk = 0).
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gcd(a,b)
= p1min(x1, y1) * p2min(x2,
y2) * .................. |
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lcm(a,b)
= p1max(x1, y1) * p2max(x2,
y2) * .................. |
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gcd(a,b)*lcm(a,b)
= p1min(x1, y1)+max(x1, y1) * p2min(x2,
y2)+max(x2, y2) * .................. =
= p1x1+y1 * p2x2+y2 * ..................
* pnxn+yn = a * b
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This was
a welcome opportunity to present an exact proof in a mathematical
notation. It was helpful to refer at each step of the proof to the
example above, so the students could follow the process.
Then
I had the idea to find another generalization: is it possible to
extend the theorem for more than two numbers?
The
students met a real challenge exploring and investigating the next
problem. And very surprisingly we could find a solution using the
trial and error method.
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| (17) |
The
above theorem might imply the consequence that we could generalize
for three numbers / expressions: |
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a
* b * c = lcm(a,b,c) * gcd(a,b,c) ?? |
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Check
the truth of that statement using two examples you choose yourself: |
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| (18) |
Try
the numbers 12, 30 and 64: |
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Are
there any triples of numbers for which that formula holds??? |
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| (19) |
Try
for (12, 18, 25): |
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| (20) |
and
now (150,210,330): |
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you explain the result? |
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| Sometimes
you can have a "mathematical feeling" but it is not so easy
to express that feeling in words. It is very important to train that
ability. |
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| (21) |
Here
is a real challenge: |
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Try
to find a relation between GCD and LCM which holds in all cases: |
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The students
found one solution:

At
the time when I was busy with this paper in school I was running
a T^3 seminar for Secondary School teachers and I presented this
paper as an example for working with the TI-92. At 10 30 in the
evening my phone rang and a colleague proudly told me that she had
found a solution:

I
wrote an e-mail to my friend Hannes Wiesenbauer and asked him for
a - better? - solution. And he - as ever and whoelse - knew the
answer. He wrote: "That problem is not so easy to solve, but
there is a solution:" and he added a theorem which leads to

The
two formulae show a wonderful symmetry and we could observe the
principle of duality which the students had met a couple of weeks
before when they had a short introduction into set theory and logic.
You might imagine that it didn´t last very long and they asked if
there was a dual formula for their product and fortunately there
was.
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| (22) |
The
binomials of the form an ± bn with n Î
N show special factorizations. Investigate these factorizations
and summarize your results in an appropriate form (in words, in a
table, formulas, rules, ......) |
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| This was home
work. I admit that this problem does not fit completely the gcd/lcm
problems but it was a welcome opportunity for me to focus once again
on pattern finding and last but not least the students had to compile
their results in an appropriate form and present the results. |
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| (23) |
Unfortunately
there is no function implemented in the TI-92 which allows
to find the GCD and LCM of general expressions. So we will try to
develop such a function. |
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Here
are two functions ggt und kgv, which are working in a way presented
on the TI-screen shown below. You should find the GCD and LCM
of the expressions |
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360a4
+ 1440a3 b + 1440a2 b2 and 45a3
– 180a b2: |
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As ggt
and kgv are related very closely:
..............................................................,
it will be sufficient
to find a function for one of them.
Do you know any application
of GCD and/or LCM?
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| We will
stick to the LCM. |
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The TI-function
getdenom(fraction) gives back the denominator of a fraction.
Try that using the following fractions:
What are the denominators
of the fractions: 
Use
to find the respective function which returns the numerator of a fraction:
.............................................
Check it: ................................................................
getdenom will support
our task to find the function kgv!
Are you ready? Do
you have a formula, which returns the LCM of two expressions t1 and t2?
Then define your function
in the following way:
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| We learn to
define a selfmade function (and later to use it). |
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kgv(t1,t2) = ............................................................................................. |
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and check its validity
by applying it to the two expressions on the TI-screen - is it
correct?
Congratulations!
But to make sure: just one more little test:
Doublecheck your function
for two numbers: kgv(3,6) = ....................
Everything ok? Why
not?? What has happened?? Find an explanation and improve the function.
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| Students should
learn not be satisfied with their results too early. It makes sense
to check the validity of rules even for very trivial cases. |
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Improved version:
define kgv(t1,t2)
= .............................................................................................
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| We can use
one function to define a new one. |
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which leads immediately
to
define ggT(t1,t2)
= .............................................................................................
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| In most cases
calculating with fractions is an underdeveloped basic skill. Even
in times of DERIVE and the TI-92 it is necessary to do simple calculations
mentally or using paper and pencil. There are a lot of textbooks and
collections of tasks together with the solutions. But it is not enough
to have the problem followed by the solution. I say: "The way
is the goal". So I tried to produce a paper to encourage students
to train their fraction-handling-skills - if necessary - with the
TI. And for that purpose they could use their selfmade kgv-function
and doublecheck their calculations step by step.. |
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| We have predefined
a function ew(expr) which returns the expanding factor for
a fraction with denominator expr and the given common denominator
gn |
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| From
the TI 92 Worksheet 3 |
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| Train
your skills in calculating and manipulating with fractions |
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Example 2:
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| Calculate
without the TI. Write down your result: ................................. |
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Here it
is.
Can you find a reason
why this calculation could cause a very special mistake?
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Compare
the common denominator and the factors used to bring all the numerators
over a common denominator.
Explain the last part
in the edit line:
-4 * gn:
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How to
work with an expanding factor
ew( )?
-4 * ew(....).
The remaining work
is very easy:
Explain the relation
between left and right hand side in the last row of the history area:
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I want to close
with a short summary. I like applied mathematics but I am sure that we
can not do without pure mathematics. I found that the students liked investigating
the problems presented and I spent a lot of time during the breaks to
answer their questions (what if?, why not?, am I right?, do you think?,....).
I never heard the question: What is the use of all that stuff? And I am
teacher at a vocational school!!! So I think we can tempt pupils to have
their "Adventures in Their Heads". And it is necessary to explain
sometimes what they have done, like: "Now you found an important
rule by your own!", "This is your first selfmade function!",...
The students are really proud and their selfconfidence is growing. There
were some very emotional moments when I felt that the sparkles were spreading
and when I then left the classroom I felt something like: "that is
it, I´ve got them". This are the precious moments when we learn why
we have become teachers. I know that the use of a CAS in whatever form
is not a necessary condition, but it is helpful in providing a new motivation
for students and ............ not to forget, for teachers, too. One example
of this species is just now standing in front of you.
What I have shown
here using the TI-92 is platform - independent. I am sure that many chapters
of our traditional curriculums can be changed and that it is not necessary
to add many new topics as a consequence of the use of modern technologies.
On the contrary, I must say, that I would now need more time in the classroom
than before, because for me mathematics teaching has a much wider scope
than ever before. And that without new subject matter.
Let me repeat in
some keyterms what we have done besides revising the chapter CLM and GCD
from Lower Secondary School (in order of appearence):
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Working
with larger numbers and expressions
Indirect
Proof
Exactness
in Editing the Data
Concept
of Nested Functions
Generalization
1
Interpretation
and Reinterpretation
Reasoning,
Defining, Checking
Using
the Manual
Pattern
Recognizing 1
Defining
and Verbalising
Proof
Generalization
2
Try
and Error, Exploring
Principle
of Duality
Giving
Reasons
Pattern
Recognizing 2
Compiling
the Results in an Appropriate Form
Defining
Functions
Using
Functions for other Functions
Checking
functions even for trivial cases
Improving
functions
Working
with the functions
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